What is the equation, in slope-intercept form, of the line that is perpendicular to the line
y-4 =-(x - 6) and passes through the point (-2,-2)?
O y=-2x - 10
O y=-x+ 10
O y=x-1
O y= {x+1

From the given we see immediately that the slope of this line is -1. The slope of a line perpendicular to this one is +1, which is the negative reciprocal of -1. The slope-intercept form is y = mx + b. To find b, the y-intercept, we make the following substitutions: m = -1, y = -2, x = -2:

-2 = +1(-2) + b, or +1 = 2 + b, or b = -1

and so the desired equation is y = x - 1 (third answer choice)

What is the equation, in slope-intercept form, of the line that is perpendicular to the line y-4 =-(x - 6) and passes through the point (-2,-2)? O y=-2x - 10 O y=-x+ 10 O y=x-1 O y= {x+1

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What is the equation, in slope-intercept form, of the line that is perpendicular to the line
y-4 =-(x - 6) and passes through the point (-2,-2)?
O y=-2x - 10
O y=-x+ 10
O y=x-1
O y= {x+1