Answer:
[tex]\boxed{\sf \ 2\sqrt{10} \ }[/tex]
Step-by-step explanation:
by definition this is [tex]\sqrt{a^2+b^2}[/tex] for a+bi
so in this case we need to compute
[tex]6^2+2^2 = 36+4=40[/tex]
and then 40=4*10=[tex]2^2*10[/tex]
So, the correct answer is [tex]\sqrt{40}=2\sqrt{10}[/tex]
to note that the magnitude is always a real number so you cannot get i in this kind of answer -> you can eliminate B
The magnitude is always positive so you can eliminate D
hope this helps
