Answer: B) 1/9, 3, 27
Step-by-step explanation:
Here, we need to evaluate [tex]3^x[/tex] for [tex]x = -2, x = 1, \text{ and } x = 3.[/tex]
So, we substitute values of x in the given function.
At x= -2, we have
[tex]3^{-2}=\dfrac{1}{3^2}=\dfrac{1}{9}\ \ \ [\because\ a^{-n}=\dfrac{1}{a^n}][/tex]
At x= 1, we have
[tex]3^1=3[/tex]
At x= 3
[tex]3^3=3\times3\times3=27[/tex]
So, the values of [tex]3^x[/tex] for
Thus, the correct answer is B) 1/9, 3, 27
