Find The equation of a circle that has it center at (-4,3) and has a radius of 5.

Answer:
A.
Step-by-step explanation:
Center = (a,b) = (-4,3)
So, a = -4, b = 3
Radius = 5
Equation of circle:
[tex](x-a)^2+(y-b)^2 = r^2[/tex]
Putting the givens
=> (x+4)²+(y-3)² = 25
[tex] {(x - h)}^{2} + {(y - k)}^{2} = {r}^{2} \\
{(x - (4))}^{2} + {(y + 3))}^{3} = {5}^{2} \\ {(x - 4)}^{2} + {(y + 3)}^{2} = 25[/tex]