Answer:
16cm^3
Step-by-step explanation:
V=1/3BH
V=1/3 (4)(4)(3)
V=16cm^3
The volume of the solid right pyramid with the length of the base edge as 4 cm and the height of the pyramid as 3 cm is 16 cm³.
The amount of three-dimensional space enclosed by a closed surface is expressed as a scalar quantity called volume.
The volume of a pyramid is one-third of the product of the base area and its height. And as given that the length of the edge of the square base is 4 cm while the height is 3 cm. Therefore, the volume of the square right pyramid can be written as,
[tex]\rm \text{Volume of Square base pyramid} = \dfrac13 \times \text{(Area of square base)} \times height[/tex]
[tex]= \dfrac13 \times (4^2) \times 3\\\\= 16 \rm\ cm^3[/tex]
Hence, the volume of the solid right pyramid with the length of the base edge as 4 cm and the height of the pyramid as 3 cm is 16 cm³.
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