Answer:
3/10
Step-by-step explanation:
Given the sample space
3 cherries
2 grapes
The sample size S = {3+2}= 5
For for the first selection
The probability of picking a grape [tex]Pr(grape)=\frac{2}{5}[/tex]
Since the second selection is without replacement the sample size is now 4
The probability of picking a cherry [tex]Pr(cherry)= \frac{3}{4}[/tex]
The probability that her brother gets a grape treat and she gets a cherry treat = [tex]\frac{2}{5} *\frac{3}{4}= \frac{6}{20}=\frac{3}{10}[/tex]
