arybulsara1946
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The vertex form of the equation of a parabola is y = (x-4)2 + 22.
What is the standard form of the equation?
O A. y = x2 + x + 11
O B. y = x2 + 8x + 22
O c. y = 4x2 - 8x + 38
O D. y = x2 - 8x+ 38​

Respuesta :

Answer:

D

Explanation:

The standard form of a quadratic function is

y = ax² + bx + c ( a ≠ 0 )

Given

y = (x - 4)² + 22 ← expand (x - 4)² using FOIL

  = x² - 8x + 16 + 22

  = x² - 8x + 38 → D

The standard form of the equation y = (x – 4)² + 22 will be y = x² – 8x + 38. Then the correct option is D.

What is the parabola?

The equation of a quadratic function, of vertex (h, k), is given by:

y = a(x – h)² + k

where a is the leading coefficient.

The vertex form of the equation of a parabola is y = (x – 4)² + 22.

The standard form of the quadratic equation is given as,

ax² + bx + c = 0

Convert the parabolic equation y = (x – 4)² + 22 into the standard form of the equation.

First, open the bracket, then the equation will be

y = (x – 4)² + 22

y = x² + 4² – 2 · 4 · x + 22

y = x² + 16 – 8x + 22

y = x² – 8x + 38

Thus, the standard form of the equation y = (x – 4)² + 22 will be y = x² – 8x + 38.

Then the correct option is D.

More about the parabola link is given below.

https://brainly.com/question/8495504

#SPJ5

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