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PLEASE HELP!!!

A school survey asked students which candidate they supported for class
president. The survey data are shown in the relative frequency table.

PLEASE HELP A school survey asked students which candidate they supported for class president The survey data are shown in the relative frequency table class=

Respuesta :

nafhausman

Answer:

18%

Step-by-step explanation:

males support to wilson =0.18

percentage will be=18%

You have the correct answer. It is choice C) 39%

We can move the decimal point 2 spots to the right for every value in the table. Doing so shows 18 males support Wilson out of 46 males total. Therefore, 18/46 = 0.39 approximately which converts to 39%

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