How can we solve question 13 algebraically? Will give brainliest + 10 points

Answer:
The answer is C.
Step-by-step explanation:
First, you have to make expressions for all the flags :
[tex]let \: blue \: flag = x[/tex]
Green flag cost 10 times the price of blue flag,
[tex]green \: flag = 10 \times x = 10x[/tex]
Red flag is half the price of green flag,
[tex]red \: flag = 10x \div 2 = 5x[/tex]
Orange is 10 dollars less than red flag,
[tex]orange \: flag = 5x - 10[/tex]
Assuming that the total cost of all 4 different coloured flags is $200. So you have to solve the value of x :
[tex]x + 10x + 5x + 5x - 10 = 200[/tex]
[tex]21x - 10 = 200[/tex]
[tex]21x = 200 + 10[/tex]
[tex]21x = 210[/tex]
[tex]x = 210 \div 21 = 10 \: dollars[/tex]
Then, you have to substitute the value of x into the expression of orange flag :
[tex]orange flag = 5x - 10[/tex]
[tex]orange flag = 5(10) - 10[/tex]
[tex]orange flag = 50 - 10[/tex]
[tex]orange flag = 40 \: dollars[/tex]