Answer:
The predicted value of y is 504.5.
Step-by-step explanation:
Let be [tex]y = 152 + 12.9\cdot x_{1} + 2.7\cdot x_{2}[/tex], for all [tex]x_{1}, x_{2} \in \mathbb{R}[/tex]. If [tex]x_{1} = 20[/tex] and [tex]x_{2} = 35[/tex], the predicted value of y is:
[tex]y = 152 + 12.9\cdot (20) + 2.7\cdot (35)[/tex]
[tex]y = 504.5[/tex]
The predicted value of y is 504.5.