Answer:
Step-by-step explanation:
The nth term of an arithmetic sequence is expressed as [tex]Tn = a+(n-1)d[/tex].
a is the first term of the sequence
d is the common difference
n is the number of terms
Given the first term a = 4 and common difference d = 3, we can calculate the first five terms of the sequence using the formula.
If n = 2
[tex]T_2 = 4+(2-1)*3\\T_2 = 4+(1)*3\\T_2 = 4+3\\T_2 = 7\\\\when \ n = 3;\\T_3 = 4+(3-1)*3\\T_3 = 4+(2)*3\\T_3 = 4+6\\T_3 = 10\\\\when\ n = 4\\T_4 = 4+(4-1)*3\\T_4 = 4+(3)*3\\T_4 = 4+9\\T_4 = 13\\\\when\ n = 5\\T_5 = 4+(5-1)*3\\T_5 = 4+(4)*3\\T_5 = 4+12\\T_5 = 16\\[/tex]
The first five terms of the sequence from lowest to highest are 4, 7, 10, 13 and 16
