Answer:
Total Weight of all the five boys is 234 kg.
Step-by-step explanation:
Given that there are five boys.
They have weighed themselves in pairs in all possible combinations.
And their weights are: 88 kg, 90 kg, 91 kg, 92 kg, 93 kg, 94 kg, 95 kg, 96 kg, 98 kg and 99 kg
To find: Total weights of the five boys = ?
Solution:
First of all, we need to find the total number of pairs that can be formed from a total of 5 number of boys.
Total number of pairs possible = [tex]_5C_2 =10[/tex]
If we select one boy, there are 4 other boys with whom pairs can be formed.
So, every boy's weight is repeated 4 number of times in these 10 pairs.
If we add all the 10 measured weights given and then divide them with 4 we will get the total weight of the five boys.
[tex]\text{Total weight of boys = } \dfrac{88+90+91+92+93+94+95+96+98+99}{4}\\\Rightarrow \text{Total weight of boys = } \dfrac{936}{4}\\\Rightarrow \text{Total weight of boys = } 234\ kg[/tex]
So, Total Weight of all the five boys is 234 kg.
