Answer: 27061
Step-by-step explanation:
given that Р = 0.5
so
1 - P = 1 - 0.5 = 0.5
ERROR OF MARGIN E = 0.01
SIGNIFICANCE LEVEL α = 1 - confidence level
α = [(1 - (99.9/100)] = 0.0010
α / 2 = 0.001 / 2 = 0.0005
Zα/2 = Z0.0005 = 3.29 (using the Z table )
therefore
Sample size n = ((Zα/2) / E)² * P * (1 - P )
Sample size n = (3.29 / 0.01)² * 0.5 * 0.5
Sample size n = 108,241 * 0.5 * 0.5
Sample size n = 27,060.25 ≈ 27,061
Answer:
sample size should be atleast n= 27069
Step-by-step explanation:
Given that,
confident level(CI) = 99%= 0.999
desired marginal error=1%= 0.01
note: marginal error = length of CL/2
significant level α = 1 - confident level = 1 - 0.999= 0.001
critical value = Zα/2 = Z(0.001/2) = Z0.0005( value of from z table) = 3.2905267
since we don't have preliminary estimate, p' = 0.5, which is require for maximum value
n = p' × (1 - p')(critical value/desired marginal)²
n= 0.5 × 0.5(3.2905267/0.01)²
n = 27068.91
the value of n has to be an integer = 27069
