Answer:
[tex]\bar X=\frac{\sum_{i=1}^n X_i}{n}[/tex]
[tex]s=\sqrt{\frac{\sum_{i=1}^n (X_i -\bar X)^2}{n-1}}[/tex]
And replacing we got:
[tex] \bar X= 58.33[/tex]
[tex]s= 10.78[/tex]
Then we can fin the limits for one deviation within the mean like this:
[tex]\mu -\sigma = 58.33-10.78= 47.55[/tex]
[tex]\mu -\sigma = 58.33+10.78= 69.11[/tex]
And then we see that the number of values between the limits are: 69, 64, 54,47 who represent 4 and then the percentage would be:
[tex]\% =\frac{4}{6}*100 =66.7\%[/tex]
Step-by-step explanation:
First we need ot calculate the mean and deviation with the following formulas:
[tex]\bar X=\frac{\sum_{i=1}^n X_i}{n}[/tex]
[tex]s=\sqrt{\frac{\sum_{i=1}^n (X_i -\bar X)^2}{n-1}}[/tex]
And replacing we got:
[tex] \bar X= 58.33[/tex]
[tex]s= 10.78[/tex]
Then we can fin the limits for one deviation within the mean like this:
[tex]\mu -\sigma = 58.33-10.78= 47.55[/tex]
[tex]\mu -\sigma = 58.33+10.78= 69.11[/tex]
And then we see that the number of values between the limits are: 69, 64, 54,47 who represent 4 and then the percentage would be:
[tex]\% =\frac{4}{6}*100 =66.7\%[/tex]
