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Suppose 27 cars start at a car race. In how many ways can the top 3 cars finish the race?
The number of different top three finishes possible for this race of 27 cars is
(Use integers for any number in the expression.)

Respuesta :

henryhuangbc

Answer:

2925

Step-by-step explanation:

27 choose 3

(27!) / (24!3!)

the 24! cancels leaving the numerator with 27 x 26 x 25

(27 x 26 x 25) / (3 x 2 x 1)

Canceling out we get

9 x 13 x 25 which works out to be

2925!

asdfghjkll175

Answer:

What expression? Anyways it is 17,550 different ways.

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