Answer:
Distances:
a = π / 2 , b = π , c = 3π /2
Heights:
d = 1 , e = 0 , f = - 1
Formula used = for distance , we use:
[tex] \frac{theta}{360} \times 2\pi \: r[/tex]
length of arc = 1 m
[tex] \frac{ \frac{\pi}{2} }{2\pi} \times 2\pi \times 1[/tex]
[tex]a \: = \: \frac{\pi}{2} [/tex]
B = [tex] \frac{\pi}{2\pi} \times 2\pi \times 1[/tex]
[tex] = \pi[/tex]
C = [tex] \frac{ \frac{3\pi}{2} \times 2\pi }{2\pi} [/tex]
[tex] = \frac{3\pi}{2} [/tex]
Heights:
If theta = π / 2 , d = 1
If theta = π , e = 0
If theta = 3π/2 , f = - 1
Please see the attached picture..
hope this helps..
Good luck on your assignment..
