xiana27
contestada

A certain rectangular prism has a height of 6 m, a length of 5 m, and a width of 4 m. Give the dimensions of a second rectangular prism that will have the same surface area of the first one.

Respuesta :

Answer:

height = length = width = [tex]\sqrt{\frac{74}{3}}[/tex]

Step-by-step explanation:

You first calculate the surface area of the given prism, by using the following formula:

[tex]A=2(wh+lw+lh)[/tex]           (1)

where

w: width = 4

h: height = 6

l: length = 5

[tex]A=2(4*6+5*4+5*6)=148[/tex]     (2)

The best way to find the dimension of another rectangular prism with the same surface area of (2), is to assume that w=h=l=a. Thus, you have in the equation (1):

[tex]A=2(3a^2)=6a^2[/tex]

You replace the value of A and solve for a:

[tex]148=6a^2\\\\a=\sqrt{\frac{148}{6}}=\sqrt{\frac{74}{3}}[/tex]

Then, the dimensions of the new prism are:

height = length = width = [tex]\sqrt{\frac{74}{3}}[/tex]

Answer:

6 m, a length of 5 m, and a width of 4 m.

Step-by-step explanation: