Students of a large university spend an average of $5 a day on lunch. The standard deviation of the expenditure is $3. A simple random sample of 36 students is taken. a) What is the expected value, standard deviation, and shape of the sampling distribution of the sample mean

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Answer and Step-by-step explanation:

According to the situation the solution is shown below:-

The expected value is

[tex]\mu = 5[/tex]

The standard deviation is

= $3

The sample distribution of the sample standard deviation is

[tex]\sigma_x = \frac{\sigma}{\sqrt{n} } \\\\ = \frac{3}{\sqrt{36} } \\\\ = \frac{3}{6}[/tex]

After solving the above equation  we will get

= 0.5

Basically we applied the applied formula so that each part could be determined