Answer:
c) 52.8 m
Step-by-step explanation:
The radius of a conical tent, r = 5.6 m
The slant height = 12 m.
The area of the canvas required to make the tent is equal to the lateral area of the cone.
[tex]\text{Lateral Area of a Cone}= \pi r l\\=\pi \times 5.6 \times 12\\=67.2\pi$ m^2[/tex]
Since the width of the canvas = 4 m
Let the length = l
Area of the canvas = 4l
[tex]4l=67.2\pi$ m^2\\l=67.2\pi \div 4\\l=52.8 m$ (correct to 1 decimal place)[/tex]
The length of the canvas required to make the tent is 52.8m.
