paulitacb16
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PLEASE HELP! The time it takes to drive from Orangeville to the Vaughan Mills Mall is normally distributed with a mean of 52 minutes and standard deviation of 5 minutes. What intervals could you estimate, using the knowledge from this activity that do not include the mean as a max or min? For example, is an interval we could estimate? However, it includes the mean as the maximum of the interval. Another example is as an example of a probability interval that we know from this activity, but it includes the mean as the minimum.

Respuesta :

MathPhys

Answer:

P(X≤57) = 84%

P(X≥57) = 16%

P(47≤X≤57) = 68%

P(X≤47) = 16%

P(X≥47) = 84%

Step-by-step explanation:

We know P(X≤52) = 50%, but this includes the mean as a maximum.

We know P(52≤X≤57) = 34%, but this includes the mean as a minimum.

But if we combine them, we get P(X≤57) = 84%.

We could also say P(X≥57) = 16%.

Since normal distributions are symmetrical, we can also show that P(47≤X≤52) = 34%.  So P(47≤X≤57) = 68%, P(X≤47) = 16%, and P(X≥47) = 84%.

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