Consider the reaction PCl5(g) ⇌ PCl3(g) + Cl2(g). If 0.02 moles of PCl5, 0.04 moles of PCl3, and 0.08 moles of Cl2 are combined in a 0.5 L flask, what is the reaction quotient (Q) before the reaction ? g

Respuesta :

Answer:

The reaction quotient (Q) before the reaction is 0.32

Explanation:

Being the reaction:

aA + bB ⇔ cC + dD

[tex]Q=\frac{[C]^{c} *[D]^{d} }{[A]^{a}*[B]^{b} }[/tex]

where Q is the so-called reaction quotient and the concentrations expressed in it are not those of the equilibrium but those of the different reagents and products at a certain instant of the reaction.

The concentration will be calculated by:

[tex]Concentration=\frac{number of moles of solute}{Volume}[/tex]

You know  the reaction:

PCl₅ (g) ⇌ PCl₃(g) + Cl₂(g).

So:

[tex]Q=\frac{[PCl_{3} ] *[Cl_{2} ] }{[PCl_{5} ]}[/tex]

The concentrations are:

  • [PCl₃]=[tex]\frac{0.04 moles}{0.5 L} =0.08 \frac{moles}{L}[/tex]
  • [Cl₂]=[tex]\frac{0.08 moles}{0.5 L} =0.16 \frac{moles}{L}[/tex]
  • [PCl₅]=[tex]\frac{0.02 moles}{0.5 L} =0.04 \frac{moles}{L}[/tex]

Replacing:

[tex]Q=\frac{0.08*0.16}{0.04}[/tex]

Solving:

Q= 0.32

The reaction quotient (Q) before the reaction is 0.32