Respuesta :
Answer:
hope dis help ;_;
Step-by-step explanation:
It's easy to see the manual solution: 1(.1) + 2(.1) + 3(.1) +......+ 30(.1).
But nobody wants to do that repetitive computation. If we factor out the (.1),
we see (.1) * (1+2+3+4...+30). Still somewhat repetitive, but not bad for just 30.
We really need a formula for big numbers though. The short cut for adding a series
of numbers is to find the average of the first and last numbers and multiply by how
many there are in the list:
(first + last)(the quantity of numbers) / 2 = (1 + 30)(30) / 2 = 465
465(.1) = $46.50
The money that Heather will save at the end of 30 days will be 465.
What is arithmetic progression?
Arithmetic progression is a sequence of numbers with a common difference. It is given by,
aₙ = a₁ + (n - 1)d
Where,
aₙ = the nᵗʰ term in the sequence
d = common difference
a₁ = first term
Now,
We have,
Heather saves one dime on the first day, two dimes on the second day, and three dimes on the third day and continues for 30 days.
So,
Money saved on the first day = 1
And,
Money save on 30 day = 30
So,
Using the sum of Arithmetic progression formula,
Sₙ = n/2 [ a + l ]
where,
n = 30
a = first term = 1
l = last term = 30
Now,
Sₙ = n/2 [ a + l ]
Sₙ = 30/2 [ 1 + 30]
Sₙ =15 × 31
Sₙ = 465
So, money saved at the end of 30 days = 465
Hence we can say that the money that Heather will save at the end of 30 days will be 465.
To learn more about arithmetic progression click here,
https://brainly.com/question/14320206
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