Answer:
The second particle will move through the field with a radius greater that the radius of the first particle
Explanation:
For a charged particle, the force on the particle is given as
[tex]F = \frac{mv^{2} }{r}[/tex]
also recall that work is force times the distance traveled
work = F x d
so, the work on the particle = F x d,
where the distance traveled by the particle in one revolution = [tex]2\pi r[/tex]
Work on a particle = 2πrF = [tex]2\pi mv^{2}[/tex]
This work is proportional to the energy of the particle.
And the work is also proportional to the radius of travel of the particles.
Since the second particle has a bigger speed v, when compared to the speed of the first particle, then, the the second particle has more energy, and thus will move through the field with a radius greater that the radius of the first particle.
