Answer:
The horizontal displacement is [tex]Adj = 114.71 \ m[/tex]
Explanation:
From the question we are told that
The angle at which the string is maintained is [tex]\theta = 41 ^o[/tex]
The length of string reeled in is [tex]l = 152 \ m[/tex]
Using the SOHCAHTOA formula
We have that the hypotenuse(Hyp) is l = 152
Hence the horizontal displacement of the kite which is the Adjacent(Adj) can be evaluated as
[tex]cos \theta = \frac{Adj}{Hyp }[/tex]
substituting values
[tex]cos(41) = \frac{Adj}{152}[/tex]
=> [tex]Adj = 114.71 \ m[/tex]
