Answer:
We can express the equation for any linear equation with slope -2 and point (x0,y0) as:
[tex]y=-2x+(y_0+2x_0)\\\\y-y_0=-2(x-x_0)[/tex]
Step-by-step explanation:
Incomplete question:
There is no point to complete the equation.
As we have no point to complete the linear equation, we will solve for any given point (x0,y0) and a slope of m=-2.
The linear equation can be written generically as:
[tex]y(x)=mx+b\\\\y(x)=-2x+b[/tex]
If a point, like (x0,y0) belongs to the linear equation, it satisfies its equation. Then:
[tex]y_0=-2x_0+b[/tex]
Then, we can calculate b as:
[tex]y_0=-2x_0+b\\\\b=y_0+2x_0[/tex]
We can express the equation for any linear equation with slope -2 and point (x0,y0) as:
[tex]y=-2x+(y_0+2x_0)\\\\y-y_0=-2(x-x_0)[/tex]
