Answer:
[tex]V_{out} = 460[/tex]
Explanation:
From your question, you already posted the answer
However, I'll give the steps to get the answer
Given
[tex]Primary\ Voltage = 230V[/tex]
[tex]Primary\ Coil = 80[/tex]
[tex]Secondary\ Coil = 160[/tex]
Required
Secondary Voltage
The relationship between the primary voltage, secondary voltage, turns of primary coil and secondary coil is as follows;
[tex]\frac{V_{out}}{V_{in}} = \frac{N_{s}}{N_{p}}[/tex]
Where
[tex]V_{in} = Primary\ Voltage = 230V[/tex]
[tex]V_{out} = Secondary\ Voltage = ??[/tex]
[tex]N_{p} = Primary\ Coil = 80[/tex]
[tex]N_{s} = Secondary\ Coil = 160[/tex]
Substitute these values in the formula above;
[tex]\frac{V_{out}}{V_{in}} = \frac{N_{s}}{N_{p}}[/tex]
becomes
[tex]\frac{V_{out}}{230} = \frac{160}{80}[/tex]
[tex]\frac{V_{out}}{230} = 2[/tex]
Multiply both sides by 230
[tex]230 * \frac{V_{out}}{230} = 2 * 230[/tex]
[tex]V_{out} = 2 * 230[/tex]
[tex]V_{out} = 460[/tex]
Hence, the secondary voltage is 460 Volts
