Answer:
0.85 ± 0.1314
Step-by-step explanation:
P*=0.85
n=49
z for 99% confidence interval = 2.576
The estimates the true proportion of UH students that are involved in a club (99% confidence interval) =
[tex]0.85\pm 2.576* \sqrt{\frac{0.85(1-0.85)}{49} } \\\\= 0.85\pm 0.1314[/tex]
=0.9814, 0.7186
We are 99% confident that the true proportion of UH students that are involved in a club is 0.85 with a margin of error of 0.1314.
