URGENT

Given that the point $(4,7)$ is on the graph of $y=3f(2x)+1$, there is one point that must be on the graph of $y=f(x)$. What is the sum of coordinates of that point?

Respuesta :

(4, 7) lies on the graph of [tex]y=3f(2x)+1[/tex], so plugging in [tex]x=4[/tex] gives [tex]y=7[/tex]:

[tex]7=3f(2\cdot4)+1\implies f(8)=2[/tex]

i.e. if [tex]x=8[/tex], then [tex]y=2[/tex], so the point (8, 2) lies on the graph of [tex]y=f(x)[/tex]. The sum of this point's coordinates is 8 + 2 = 10.

Otras preguntas