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Pulling out of a dive, the pilot of an airplane guides his plane into a vertical circle with a radius of 600 m. At the bottom of the dive, the speed of the airplane is 150 m/s. What is the apparent weight of the 70.0-kg pilot at that point?

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onyebuchinnaji

Answer:

The apparent weight of the pilot is 3311 N

Explanation:

Given;

radius of the vertical circle, r = 600 m

speed of the plane, v = 150 m/s

mass of the pilot, m = 70 kg

Weight of the pilot due to his circular motion;

[tex]W= F_v\\\\F_v = \frac{mv^2}{r} \\\\F_v = \frac{70*150^2}{600} \\\\F_v = 2625 \ N[/tex]

Real weight of the pilot;

[tex]W_R = mg\\\\W_R = 70 *9.8\\\\W_R = 686 \ N[/tex]

Apparent weight - Real weight of pilot = weight due to centripetal force

[tex]F_N - mg = \frac{mv^2}{r} \\\\F_N = \frac{mv^2}{r} + mg\\\\F_N = 2625 \ N + 686 \ N\\\\F_N = 3311\ N[/tex]

Therefore, the apparent weight of the pilot is 3311 N

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