Answer:
The solutions of 2·cos(θ) - √3 = 0in the interval [0, 2pi) are;
π/6, 13/6·π
Step-by-step explanation:
The given that the equation is 2·cos(θ) - √3 = 0
The solution of the above equation in the interval [0, 2pi) are required
Therefore, the domain includes 0 ≤ θ < 2pi
2·cos(θ) - √3 = 0
2·cos(θ) = √3
cos(θ) = √3/2
Therefore;
θ = cos⁻¹(√3/2)
The values are;
[tex]\theta =\dfrac{12 \cdot \pi \cdot n_1 +\pi }{6} \, or \, \theta =-\dfrac{12 \cdot \pi \cdot n_1 +\pi }{6}[/tex]
Where the domain is 0 ≤ θ < 2pi, we have;
π/6, 13/6·π
