Answer:
Pyramid
Step-by-step explanation:
[tex]\text{Volume of a Square Pyramid }=\frac{1}{3} \times l^2 \times Height\\\\ \text{Volume of a Cone }=\frac{1}{3} \pi r^2 \times Height[/tex]
Given that the two solids have the same volume
[tex]\frac{1}{3} \times l^2 \times Height=\frac{1}{3} \pi r^2 \times Height[/tex]
If the length of a side of the square base of pyramid A is the same as the base radius of cone B. i.e l=r
[tex]\frac{1}{3} \times l^2 \times $Height of Pyramid=$\frac{1}{3} \pi l^2 \times $Height of cone$\\\\$Cancel out $ \frac{1}{3} \times l^2$ on both sides\\\\Height of Pyramid= \pi \times $ Height of cone$[/tex]
If the height of the cone is 1
[tex]H$eight of Pyramid= \pi \times 1 \approx 3.14$ units[/tex]
Therefore, the pyramid has a greater height.
