Answer:
The function has two real roots and crosses the x-axis in two places.
The solutions of the given function are
x = (-0.4495, 4.4495)
Step-by-step explanation:
The given quadratic equation is
[tex]G(x) = -x^2 + 4x + 2[/tex]
A quadratic equation has always 2 solutions (roots) but the nature of solutions might be different depending upon the equation.
Recall that the general form of a quadratic equation is given by
[tex]a^2 + bx + c[/tex]
Comparing the general form with the given quadratic equation, we get
[tex]a = -1 \\\\b = 4\\\\c = 2[/tex]
The nature of the solutions can be found using
If [tex]b^2- 4ac = 0[/tex] then we get two real and equal solutions
If [tex]b^2- 4ac > 0[/tex] then we get two real and different solutions
If [tex]b^2- 4ac < 0[/tex] then we get two imaginary solutions
For the given case,
[tex]b^2- 4ac \\\\(4)^2- 4(-1)(2) \\\\16 - (-8) \\\\16 + 8 \\\\24 \\\\[/tex]
Since 24 > 0
we got two real and different solutions which means that the function crosses the x-axis at two different places.
Therefore, the correct option is the last one.
The function has two real roots and crosses the x-axis in two places.
The solutions (roots) of the equation may be found by using the quadratic formula
[tex]$x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}$[/tex]
[tex]x=\frac{-(4)\pm\sqrt{(4)^2-4(-1)(2)}}{2(-1)} \\\\x=\frac{-4\pm\sqrt{(16 - (-8)}}{-2} \\\\x=\frac{-4\pm\sqrt{(24}}{-2} \\\\x=\frac{-4\pm 4.899}{-2} \\\\x=\frac{-4 + 4.899}{-2} \: and \: x=\frac{-4 - 4.899}{-2}\\\\x= -0.4495 \: and \: x = 4.4495 \\\\[/tex]
Therefore, the solutions of the given function are
x = (-0.4495, 4.4495)
A graph of the given function is also attached where you can see that the function crosses the x-axis at these two points.
