Answer:
The function graphed below is [tex]x = y^{2} - 2[/tex] or [tex]y = \pm \sqrt{x+2}[/tex].
Step-by-step explanation:
The graph represents a second order polynomial function (a parabola), whose axis of symmetry is the x-axis and whose form is presented as follows:
[tex]x - h = C\cdot (y-k)^{2}[/tex]
Where:
[tex]x[/tex], [tex]y[/tex] - Dependent and independent variable, dimensionless.
[tex]h[/tex], [tex]k[/tex] - Horizontal and vertical components of the vertex, dimensionless.
[tex]C[/tex] - Vertex constant, dimensionless. If [tex]C > 0[/tex], then vertex is an absolute minimum, otherwise it is an absolute maximum.
After a quick observation, the following conclusions are done:
1) Vertex is an absolute minimum ([tex]C > 0[/tex]) and located at (-2, 0).
2) Parabola pass through (2, 2).
Then, the value of the vertex constant is obtained after replacing all known values on expression prior algebraic handling: ([tex]x = 2[/tex], [tex]y = 2[/tex], [tex]h = -2[/tex], [tex]k = 0[/tex])
[tex]2+2 = C\cdot (2-0)^{2}[/tex]
[tex]4 = 4\cdot C[/tex]
[tex]C = 1[/tex]
The function is:
[tex]x = -2 + 1\cdot y^{2}[/tex]
[tex]x = y^{2}-2[/tex]
The inverse function of this expression is [tex]y = \pm \sqrt{x+2}[/tex]
The function graphed below is [tex]x = y^{2} - 2[/tex] or [tex]y = \pm \sqrt{x+2}[/tex].
