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Parallel lines p and q are cut by transversal r. On line p where it intersects with line r, 4 angles are created. Labeled clockwise, from the uppercase left, the angles are: 1, 2, 4, 3. On line q where it intersects with line r, 4 angles are created. Labeled clockwise, from the uppercase left, the angles are: 5, 6, 8, 7. m∠3 is (3x + 4)° and m∠5 is (2x + 11)°. Angles 3 and 5 are . The equation can be used to solve for x. m∠5 = °

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devishri1977

Answer:

m∠5 = 77

Step-by-step explanation:

∠3 & ∠ 5 are the co interior angles in the same side of the transversal

∠3 + ∠5 = 180 {sum of co interior angles is 180}

3x + 4 + 2x +11 = 180  {Add like terms}

5x + 15 = 180

Subtract 15 from both sides

5x + 15 - 15 = 180 -15

5x = 165

Divide both side by 5

5x/5 = 165/5

x = 33°

m∠5 = 2x + 11 = 2*33 + 11

        = 66 + 11

       = 77

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