Answer:
The distance covered by the cheetah during the motion is 77.75 m
Explanation:
Given;
initial velocity of cheetah, u = 0
final velocity of cheetah, v = 25 m/s
time of acceleration, t = 6.22 s
Apply kinematic equation;
[tex]s = (\frac{v+u}{2} )t[/tex]
where;
s is the distance covered by the cheetah during the motion
[tex]s = (\frac{v+u}{2} )t\\\\s = (\frac{25+0}{2} )6.22\\\\s = 77.75 \ m[/tex]
Therefore, the distance covered by the cheetah during the motion is 77.75 m
