[tex] \huge{ \underline{ \boxed{ \bf{ \blue{Solution:}}}}}[/tex]
Provided:-
- Initial velocity = 15 m/s
- Final velocity = 10 m/s
- Time taken = 2 s
To FinD:-
- Accleration of the particle....?
How to solve?
We will solve the above Question by using equations of motion that are:-
- v = u + at
- s = ut + 1/2 at²
- v² = u² + 2as
Here,
- v = Final velocity
- u = Initial velocity
- a = acceleration
- t = time taken
- s = distance travelled
Work out:
By using first equation of motion,
⇛ v = u + at
⇛ 10 = 15 + a(2)
⇛ -5 = 2a
Flipping it,
⇛ 2a = -5
⇛ a = -2.5 m/s² [ANSWER]
❍ Acclearation is negative because final velocity is less than Initial velocity.
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