Answer:
a
[tex]H_3 = 0.85 \ m[/tex]
b
[tex]PE = 0.3528 \ J[/tex]
Explanation:
From the question we are told that
The coefficient of resolution is [tex]C_r = 0.90[/tex]
The initial height is [tex]H_i = 1.60 \ m[/tex]
Considering question a
The number of times the ball bounced is [tex]k = 3[/tex]
Generally the height attained after the 3rd bounce is mathematically represented as
[tex]H_3 = H_i * (C_r)^{2 * k }[/tex]
=> [tex]H_3 = 1.60 * 0.90^{2 * 3 }[/tex]
=> [tex]H_3 = 0.85 \ m[/tex]
Considering question b
The mass is m = 48 g = 0.048 kg
Generally the amount of potential energy that was lost is mathematically represented as
[tex]PE = mg [ H_i - H_3 ][/tex]
=> [tex]PE = 0.048 * 9.8 [1.60 - 0.85 ][/tex]
=> [tex]PE = 0.3528 \ J[/tex]
