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One train is at the 20 Km position, another is at the 200Km position, both are approaching, the first with a speed of 30Kmh-1 and the second with a speed of 48 Kmh-1. If they leave at 7:12, what time do they cross? Answer: t = 2.30 H Time: 9:30 am.

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MathPhys

Explanation:

The distance between them is 200 km − 20 km = 180 km.

The relative velocity is 30 km/h − (-48 km/h) = 78 km/h.

The time it takes is 180 km / (78 km/h) = 2.31 hours, or 2 hrs 18 min.

Therefore, the trains meet at 9:30 AM.

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