Respuesta :
Answer:
Yes
Step-by-step explanation:
You can find the answer to this question by finding the value of x in both equations.
Let's start off with the first equation: [tex]x+4=5[/tex]
To find the value of x, you're going to have to subtract 4 from both sides. This is because you're looking for the value of only x, not x + 4. To leave x alone, you'd have to subtract 4, leaving that side with just x.
[tex]x+4-4=5-4[/tex]
[tex]x=1[/tex]
The answer to the first equation is x = 1.
Now let's start on the second equation: [tex]2x+8=10[/tex]
Like before, you're looking for x alone and in this equation, 8 is being added to 2x. Although x itself isn't alone, you'll first start off with 2x since you can simplify it thrughout the process. In this equation, you're going to subtract 8 from both sides to leave the variable x alone.
[tex]2x+8-8=10-8[/tex]
[tex]2x=2[/tex]
Now you're left with 2x = 2. Since you're looking for the value of x alone, you're going to divide both sides by 2. Because x is being multiplied by 2(2 times x = 2x) you're going to divide(opposite of multiply), which will cancel out the 2(in 2x).
[tex]\frac{2x}{2} = \frac{2}{2}[/tex]
[tex]x = 1[/tex]
The answer to the second equation is x = 1.
Since both equations have the same solution, the answer to your question would be yes.
Hello There!
ANSWER:
Yes
EXPLANATION:
If you want to know if your two equations are equivalent, let's try finding the answer to both of them.
[tex]x+4=5[/tex]
Let's find x.
We all know addition and subtraction. So let's just do
[tex]5-4=x[/tex]
So 5-4 is equal to 1.
So the answer for this equation is
[tex]x=1[/tex]
Let's move on to your second equation.
[tex]2x+8=10[/tex]
Now we must subtract 8 from both sides.
[tex]2x+8-8=10-8[/tex]
And this equals
[tex]2x=2[/tex]
Let's divide the both sides by 2.
[tex]\frac{2x}{2}=\frac{2}{2}[/tex]
The fraction [tex]\frac{2}{2}[/tex] is gonna equal one.
So [tex]x=1[/tex]
Now you have your answer for the second equation. Both answers were the same.
So the answer to your question is YES.
