Complete the equation. Answer as a fraction in its simplest form.
9xy * (2/3x)*3 = ( [ ] a0 / [ ] a1 ) x*4y

Answer:
Step-by-step explanation:
[tex]9xy\cdot(\frac{2}{3}x)^3=3^2xy\cdot\dfrac{2^3x^3}{3^3}\\\\=\dfrac{8}{3^{3-2}}x^4y=\boxed{\dfrac{8}{3}}x^4y[/tex]
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The applicable rules of exponents are ...
(ab)^c = (a^c)(b^c)
(a^b)/(a^c) = 1/(a^(c-b))