Respuesta :
Answer:
The P-value is 0.0353.
Step-by-step explanation:
We are given the six measurements of a sprinter's reaction time show below;
X = 0.152, 0.154, 0.166, 0.147, 0.161, and 0.159 seconds.
Let [tex]\mu[/tex] = mean sprinter's reaction time
So, Null Hypothesis, [tex]H_0[/tex] : [tex]\mu \leq[/tex] 0.150 seconds {means that the mean sprinter's reaction time is at most 0.150 seconds}
Alternate Hypothesis, [tex]H_A[/tex] : [tex]\mu[/tex] > 0.150 seconds {means that the mean sprinter's reaction time is more than 0.150 seconds}
The test statistics that will be used here is One-sample t-test statistics because we don't know about the population standard deviation;
T.S. = ~
where, [tex]\bar X[/tex] = sample mean = [tex]\frac{\sum X}{n}[/tex] = [tex]\frac{0.939}{6}[/tex] = 0.1565 seconds
s = sample standard deviation = [tex]\sqrt{\frac{\sum (X-\bar X)^{2} }{n-1} }[/tex] = 0.0068 seconds
n = sample of measurements = 6
So, the test statistics = [tex]\frac{0.1565-0.150}{\frac{0.0068}{\sqrt{6} } }[/tex] ~ [tex]t_5[/tex]
= 2.341
The value of t-test statistics is 2.341.
Now, the P-value of the test statistics is given by the following formula;
P-value = P( > 2.341) = 0.0353.
{Interpolating between the critical values at 5% and 2.5% significance level}
