Answer:
V= 68.6 m/s
Step-by-step explanation:
height above the ground t seconds after it is dropped is 675-4.9t^2
For seven seconds
Height above ground= 675-4.9(7)²
height above ground= 675-240.1
Height above ground= 434.9 m
But it's dropped from a cliff and we need to find the distance traveled from the too of the cliff
Distance= 675-434.9.
Distance= 240.1
To determine it's speed
V²= U² +2gs
V= velocity we are looking for
U= initial velocity= 0
G= acceleration due to gravity= 9.8 m/s²
s= distance covered
V²= U² +2gs
V²= 0+2(9.8)(240.1)
V²= 4705.96
V= 68.6 m/s