An airplane travels 2100 km at 1000km/hE. It encounters a wind and slows to 800 km/h E for the next 1300 km. What is the average velocity of the airplane for this trip?

Respuesta :

Answer:

The average velocity of the airplane for this trip is 1684.21 km/h

Explanation:

Average velocity is the rate of change of displacement with time. That is,

Average velocity = [tex]\frac{Displacement }{Change in time}[/tex] = Δx / Δt = [tex]\frac{x2 - x1}{t2 - t1}[/tex]

Now we will calculate the time taken by the airplane for the first motion before it encounters a wind.

From,

Velocity = [tex]\frac{Distance traveled}{Time taken}[/tex]

Time = [tex]\frac{Distance traveled}{Velocity}[/tex]

Therefore, Time = [tex]\frac{2100km }{1000km/h}[/tex]

Time = 2.1h

This is the time taken before the airplane encounters a wind.

Hence, t1 = 2.1h

Now, For the time taken by the airplane when it encounters a wind

Also from,

Velocity = [tex]\frac{Distance traveled}{Time taken}[/tex]

Time = [tex]\frac{Distance traveled}{Velocity}[/tex]

Therefore, Time = [tex]\frac{1300km }{800km/h}[/tex]

Time = 1.625h

Hence, t2 = 1.625h

Now, to calculate the average velocity

Average velocity = [tex]\frac{x2 - x1}{t2 - t1}[/tex]

x1= 2100, x2= 1300, t1= 2.1h and t2= 1.625h

Hence, Average velocity = [tex]\frac{1300 - 2100}{1.625 - 2.1}[/tex]

Average velocity = 1684.21 km/h