Respuesta :

Answer:

Qsp > ksp

Explanation:

given data

Ag2CrO4 = 9.0 × [tex]10^{-12}[/tex]

solution

new [[tex]Ag^+[/tex]] = [tex]\frac{0.005 \times 200}{200+300}[/tex] = 0.002 M     .................1

and

new [[tex]CrO^{2-}_4[/tex]] = [tex]\frac{0.002 \times 300}{200+300}[/tex]  = 0.0012M    ..............2

so here solubility equation will be as

[tex]Ag_2CrO_4(s)[/tex] ⇄  2[tex]Ag^+[/tex] (aq) + [tex]CrO^{2-}_4[/tex] (aq)    ......................3

so

Qsp = [tex][Ag^+]^2[/tex] [ [tex]CrO^{2-}_4[/tex]]

put here value

Qsp = (0.002)² × (0.0012)

Qsp = 4.80 × [tex]10^{-9}[/tex]  

so that we can say that Qsp > ksp

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