Respuesta :
Answer:
N2 + O2 → 2NO is an oxidation-reduction reaction.
Explanation:
An oxidation-reduction reaction (also know as Redox reaction) is a type of chemical reaction that involves a transfer of electrons between two species. It occurs when the oxidation number of a molecule, atom, or ion changes by gaining or losing an electron.
We will consider the equations one after the other.
- KOH + HNO3 → H2O + KNO3
Oxidation numbers of the individual element on the reactant side:
KOH : K = +1, O = -2, H = +1
HNO3 : H = +1, N = +5, O = -2
Oxidation numbers of the individual element on the product side:
H2O: H = +1, O = -2
KNO3: K = +1, N = +5, O = -2
There is no change in the oxidation numbers, hence, it is not an oxidation-reduction reaction.
- CaCl2 + Na2SO4 → CaSO4 + 2NaCl
Oxidation numbers of the individual element on the reactant side:
CaCl2 : Ca = +2, Cl = -1
Na2SO4: Na = +1, S = +6, O = -2
Oxidation numbers of the individual element on the product side:
CaSO4: Ca = +2, S = +6, O = -2
NaCl: Na = +1, Cl = -1
There is no change in the oxidation numbers, hence, it is not an oxidation-reduction reaction.
- AgNO3 + NaCl → AgCl + NaNO3
Oxidation numbers of the individual element on the reactant side:
AgNO3: Ag = +1, N = +5, O = -2
NaCl: Na = +1, Cl = -1
Oxidation numbers of the individual element on the product side:
AgCl: Ag = +1, Cl = -1
NaNO3: Na: +1, N = +5, O = -2
There is no change in the oxidation numbers, hence, it is not an oxidation-reduction reaction.
- Al2(SO4) 3 + 6KOH → 2Al(OH)3 + 3K2SO4
Oxidation numbers of the individual element on the reactant side:
Al2(SO4)3: Al =+3, S = +6, O = -2
KOH: K = +1, O = -2, H = +1
Oxidation numbers of the individual element on the product side:
Al(OH)3: Al =+3, O = -2, H = +1
K2SO4: K = +1, S = +6, O = -2
There is no change in the oxidation numbers, hence, it is not an oxidation-reduction reaction.
- N2 + O2 → 2NO
Oxidation numbers of the individual element on the reactant side:
N2: N = 0
O2: O = 0
Oxidation numbers of the individual element on the product side:
NO: N = +2, O = -2
There are changes in the oxidation numbers, hence, it is an oxidation-reduction reaction.
The following is an oxidation-reduction reaction - N2 + O2 → 2NO
Oxidation numbers represent the potential charge of an atom in its ionic state. If the oxidation number decreases in a reaction, it is reduced. If an atom's oxidation number increases, it is oxidized.
- CaCl2 + Na2SO4 → CaSO4 + 2NaCl is a double displacement reaction
- KOH + HNO3 → H2O + KNO3 is acid-base neutralization reaction
- AgNO3 + NaCl → AgCl + NaNO3 is double displacement reaction
- Al2(SO4) 3 + 6KOH → 2Al(OH)3 + 3K2SO4 is double displacement reaction
- All three reaction mention above is not oxidation-reduction reaction as each atom has the same oxidation number in these reactions.
- N2 + O2 → 2NO is oxidation-reduction reaction.
= > Oxidation state of N in the reactant is 0
=> Oxidation state of N in the product is +2
So, N is oxidized
=> Oxidation state of O in the reactant is 0
=> Oxidation state of O in the product is -2
So, O is reduced
Thus, the following is an oxidation-reduction reaction - N2 + O2 → 2NO
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