Answer:
The side length of the square is 3 meters.
The side length of the triangle is 4 meters.
Step-by-step explanation:
This is basically a systems of equations word problem.
To solve this, we have to create two different equations. Let's assume [tex]s[/tex] is the side length of the square and [tex]t[/tex] is the side length of the triangle.
We can make the equation [tex]4s=3t[/tex], since the perimeters are the same. (A square has 4 sides, a triangle has 3 - multiplying by the side length of each will get perimeter)
We also know that the side length of the triangle is 1 meter longer than the side length of the square, so the equation here becomes [tex]t = s+1[/tex].
Now, let's substitute the second equation ([tex]t = s+1[/tex]) into the first ([tex]4s=3t[/tex]).
[tex]4s = 3(s+1)[/tex]
Apply the distributive property:
[tex]4s = 3s+3[/tex]
Subtract 3s from both sides:
[tex]s=3[/tex]
So the side length of the square is 3. We can now plug it into the equation [tex]t = s + 1[/tex] to find the side length of the triangle.
[tex]t = 3+1\\\\t=4[/tex]
Hope this helped!