If x = 39, y = 58, and the measure of AC = 4 units, what is the difference in length between segments AB and AD? Round your answer to the nearest hundredth. 0.74 units 1.17 units 1.64 units 2.14 units

The difference in length between segments AB and AD is 1.63935 units.
We have given that,
If x = 39, y = 58, and the measure of AC = 4 units, what is the difference in length between segments AB and AD Round your answer to the nearest hundredth. 0.74 units 1.17 units 1.64 units 2.14 units.
[tex]sin(x)=\frac{Opposite \ side}{hypotenuse}[/tex]
sin 39=AC/AB
AB=AC/sin39
=4/sin39
[tex]=6.35606[/tex]
TO FIND AD:
sin 58=AC/AD
AD=AC/sin58
=4/sin58
[tex]=4.71671[/tex]
The is difference between AB and AD is the length
AB-AD=6.35606-4.71671
AB-AD= 1.63935 units
The difference in length between segments AB and AD is 1.63935 units.
To learn more about the length of visit:
https://brainly.com/question/2217700
#SPJ2