If x = 39, y = 58, and the measure of AC = 4 units, what is the difference in length between segments AB and AD? Round your answer to the nearest hundredth. 0.74 units 1.17 units 1.64 units 2.14 units

If x 39 y 58 and the measure of AC 4 units what is the difference in length between segments AB and AD Round your answer to the nearest hundredth 074 units 117 class=

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Answer:

1.64

Step-by-step explanation:

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The difference in length between segments AB and AD is 1.63935 units.

We have given that,

If x = 39, y = 58, and the measure of AC = 4 units, what is the difference in length between segments AB and AD Round your answer to the nearest hundredth. 0.74 units 1.17 units 1.64 units 2.14 units.

What is the formula for the sign ratio?

[tex]sin(x)=\frac{Opposite \ side}{hypotenuse}[/tex]

sin 39=AC/AB

AB=AC/sin39

=4/sin39

[tex]=6.35606[/tex]

TO FIND AD:

sin 58=AC/AD

AD=AC/sin58

=4/sin58

[tex]=4.71671[/tex]

The is difference between AB and AD is the length

AB-AD=6.35606-4.71671

AB-AD= 1.63935 units

The difference in length between segments AB and AD is 1.63935 units.

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