In the following problems, suppose J is between H and K.
• Use Segment Addition Postulate to solve for x.
• Then find the length of each segment.

11. HJ=6x-5
JK=4x-6
KH=129

12. HJ=4x-15
JK=5x-6
KH=15

Please show all work and not just answers.

Respuesta :

Answer:

  11. HJ = 79; JK = 50

  12. HJ = 1; JK = 14

Step-by-step explanation:

The segment addition postulate tells you the total length is the sum of the segment lengths.

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11. HJ + JK + HK

  (6x -5) +(4x -6) = 129

  10x = 140 . . . . add 11

  x = 14 . . . . . . . divide by 10

  6x -5 = 6(14) -5 = 79 = HJ

  4x -6 = 4(14) -6 = 50 = JK

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12. HJ + JK = HK

  (4x -15) +(5x -6) = 15

  9x = 36 . . . . . add 21

  x = 4 . . . . . . . .divide by 9

  4(4) -15 = 1 = HJ

  5(4) -6 = 14 = JK