Answer:
A length of 5 and a perimeter of 20
Step-by-step explanation:
Personally, I'm lactose intolerant so I wouldn't take any Cheez-Its, but oh well.
Everyone wants the most Cheez-its, right? So we need to find the rectangle with the greatest area.
Let's look at the first one, a rectangle with a length of 9 and a perimeter of 22.
The perimeter of a rectangle can be expressed as [tex]2l+2w[/tex], where l is the length and w is the width.
We know the length and area, so let's solve for w (the width).
[tex]2\cdot9+2w=22\\\\18+2w=22\\\\2w=4\\\\w=2[/tex]
So the width is 2. The area of a rectangle is the length times the width.
[tex]9\cdot2=18[/tex]
So the first rectangle has an area of 18.
Using the same concept for the second statement, a length of 5 and a perimeter of 20, we can find the area.
[tex]2l+2w=20\\\\2\cdot5+2w=20\\\\10+2w=20\\\\2w=10\\\\w=5\\\\5\cdot5=25[/tex]
So the area of the second one is 25.
The greatest area is 25, so you'd want this one.
Hope this helped!
