Answer:
D
Step-by-step explanation:
Instead of going through each of the table, let's create one ourselves.
So, we have the piecewise function:
[tex]f(x)=-x+8,\text{ if } x<4\\f(x)=x, \text{ if } x\geq 4[/tex]
So, let's create a table of values starting with 2 and skipping the odd numbers until 12.
2:
For 2, since 2 is less than one, plug it into the first equation. Thus:
[tex]f(2)=-(2)+8=6[/tex]
So, the first value is (2,6).
For 4, since 4 is not less than 4 but rather equal to 4, use the second equation. Thus:
[tex]f(4)=(4)=4[/tex]
The second value is (4,4).
For 6, the same thing. 6 is greater than 4 so use the second equation:
[tex]f(6)=(6)=6[/tex]
So the third value is (6,6).
And this pattern will repeat. Therefore, our table of equations is:
x | y
2 | 6
4 | 4
6 | 6
8 | 8
10 | 10
12 | 12
The choice that represents this is D. D is the correct answer.
